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6x^2-55x-56=0
a = 6; b = -55; c = -56;
Δ = b2-4ac
Δ = -552-4·6·(-56)
Δ = 4369
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-\sqrt{4369}}{2*6}=\frac{55-\sqrt{4369}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+\sqrt{4369}}{2*6}=\frac{55+\sqrt{4369}}{12} $
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